if-else conditional statement

In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow:

Source: Wikipedia

Task
Given an integer, , perform the following conditional actions:

• If  is odd, print Weird
• If  is even and in the inclusive range of  to , print Not Weird
• If  is even and in the inclusive range of  to , print Weird
• If  is even and greater than , print Not Weird

Complete the stub code provided in your editor to print whether or not  is weird.

Input Format

A single line containing a positive integer, .

Constraints

Output Format

Print Weird if the number is weird; otherwise, print Not Weird.

Sample Input 0

3

Sample Output 

Weird

Sample Input 1

24

Sample Output 1

Not Weird

Explanation

Sample Case 0: 
 is odd and odd numbers are weird, so we print Weird.

Sample Case 1: 
 and  is even, so it isn't weird. Thus, we print Not Weird.

Java program:

import java.io.*;

import java.math.*;

import java.security.*;

import java.text.*;

import java.util.*;

import java.util.concurrent.*;

import java.util.regex.*;

public class Solution {

    public static void main(String[] args) {

        Scanner sc = new Scanner(System.in);

        int a = sc.nextInt();

        if((a%2==0 && a>20) || (a%2==0 && a>=2 && a<=5))

        {

            System.out.println("Not Weird");

        }

        else

            System.out.println("Weird");

        sc.close();

    }

}

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
public class Solution {
    public static void main(String[] args) {
        try{
        BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
        int N=Integer.parseInt(br.readLine().trim());
        if(N<1||N>100)
            throw new Exception();
        if((N&1)==1)
        {
            System.out.println("Weird");
        }
        else
        {
            if(N>=2&&N<=5)
            {
                System.out.println("Not Weird");
            }
            else if(N>=6&&N<=20)
            {
                System.out.println("Weird");
            }
            else
            {
                System.out.println("Not Weird");
            }
        }
        }
        catch(Exception e)
        {
            e.printStackTrace();
        }
    }
}

Java Program 3:

import java.io.*;

import java.util.*;

import java.text.*;

import java.math.*;

import java.util.regex.*;

public class Solution {

    public static void main(String[] args) {

        Scanner sc=new Scanner(System.in);

        int n=sc.nextInt();            

        String ans;

        if(n%2==1)ans = "Weird";

        else

        {

            if(n>=2 && n<=5)ans = "Not Weird";

            else if(n>=5 && n<=20)ans="Weird";

            else ans = "Not Weird";

        }

        System.out.println(ans);

    }

}